http://sql-question.blogspot.in/2012/10/what-is-tally-table-in-sql-server.html
I use Tally table to generate 25 years of dates, so my Tally tables will have values from 1 to 10,000 (25 years * 365.25 days = 9131.25)
SET NOCOUNT ON;
IF OBJECT_ID('dbo.Tally') IS NOT NULL DROP TABLE dbo.Tally
GO
-- Define how many rows you want in Tally table.
-- I am inserting only 10000 rowsSET ROWCOUNT 10000
SELECT IDENTITY(INT, 1, 1) ID
INTO dbo.Tally
FROM master.sys.all_columns c
CROSS JOIN master.sys.all_columns c1
-- you may use one more cross join if tally table required hundreds of million rows
SET ROWCOUNT 0
-- ADD (unique) clustered indexCREATE UNIQUE CLUSTERED INDEX PKC_Tally ON dbo.Tally (ID)
GO
How to use Tally table in T-SQL and what are the
advantages?
SELECT DATEADD(DD, ID-1, @BeginDate) [Date]
,DAY(DATEADD(DD, ID-1, @BeginDate)) [Day]
,MONTH(DATEADD(DD, ID-1, @BeginDate)) [Month]
,YEAR(DATEADD(DD, ID-1, @BeginDate)) [Year]
FROM dbo.Tally
WHERE ID <= DATEDIFF(DD, @BeginDate, @EndDate) + 1
Find a Character Positions in a String using Tally Table
SET @Str = 'Hari,Jon,Ravi,Vijay,Peter,Max' --Input String
SELECT ID AS CharPosition
FROM dbo.Tally
WHERE ID <= LEN(@Str)
AND SUBSTRING(@Str, ID, 1) = @FindChar
ORDER BY ID
Find count of all the occurrences of a Character in a String using Tally Table
SET @Str = 'Hari,Jon,Ravi,Vijay,Peter,Max' --Input String
SELECT ID AS CharPosition
FROM dbo.Tally
WHERE ID <= LEN(@Str)
AND SUBSTRING(@Str, ID, 1) = @FindChar
) AS Temp
Split Comma Seperated values using Tally table
SET @Str = 'Hari,Jon,Ravi,Vijay,Peter,Max'
WHERE ID < LEN(@Str)
AND SUBSTRING(@Str, ID, 1) = @Delimiter
A Tally
table is like any other table but having a single column of sequential numbers,
values starting from 1 (or 0) to some N (int) number.
The largest number in the Tally table should be
based on what suits your system, application, or database most. So don't use very high number.
Also column of Tally should be indexed for better
performance.I use Tally table to generate 25 years of dates, so my Tally tables will have values from 1 to 10,000 (25 years * 365.25 days = 9131.25)
How to Create a Tally
Table
There
are several methods to create a Tally table. I will use one of the simplest and
obvious option - WHILE loop because it's easier to explain and simpler than
others.SET NOCOUNT ON;
IF OBJECT_ID('dbo.Tally') IS NOT NULL DROP TABLE dbo.Tally
GO
-- Define how many rows you want in Tally table.
-- I am inserting only 10000 rowsSET ROWCOUNT 10000
SELECT IDENTITY(INT, 1, 1) ID
INTO dbo.Tally
FROM master.sys.all_columns c
CROSS JOIN master.sys.all_columns c1
-- you may use one more cross join if tally table required hundreds of million rows
SET ROWCOUNT 0
-- ADD (unique) clustered indexCREATE UNIQUE CLUSTERED INDEX PKC_Tally ON dbo.Tally (ID)
GO
There are several advantages
of a Tally table. Here are some of the examples:
I will explain these
advantages with examples.
Generate Date Range using Tally Table
Ø
To
generate Date Range for given Start Date and End
Date
Ø
To Manipulate strings,
like:
·
Find the positions of a
character in a string.
·
Find the total occurances of
a character in a string
·
Split comma seperated
values
Generate Date Range using Tally Table
Generally
you would require a WHILE loop to create Date Range values. However, it is very
easy to generate date range using tally. Its much
faster than WHILE loop:
--
Generate Date range
DECLARE
@BeginDate DATE = '2001-01-01', @EndDate DATE = '2025-12-31'SELECT DATEADD(DD, ID-1, @BeginDate) [Date]
,DAY(DATEADD(DD, ID-1, @BeginDate)) [Day]
,MONTH(DATEADD(DD, ID-1, @BeginDate)) [Month]
,YEAR(DATEADD(DD, ID-1, @BeginDate)) [Year]
FROM dbo.Tally
WHERE ID <= DATEDIFF(DD, @BeginDate, @EndDate) + 1
Here
is the output:
Find a Character Positions in a String using Tally Table
You
can find a character position using string functions and WHILE loop. But Tally
table makes it much simpler than any other method, yet faster. Here is an
example:
-- Find the
position numbers of comma in a given string.
DECLARE @Str VARCHAR(1000), @FindChar CHAR(1) = ','SET @Str = 'Hari,Jon,Ravi,Vijay,Peter,Max' --Input String
SELECT ID AS CharPosition
FROM dbo.Tally
WHERE ID <= LEN(@Str)
AND SUBSTRING(@Str, ID, 1) = @FindChar
ORDER BY ID
Here
is the output:
Find count of all the occurrences of a Character in a String using Tally Table
You
can find the count of all the occurrences of a character in a string using Tally
table by slightly modifying above query:
-- Find the
occurrences of a character in a given string.
DECLARE @Str VARCHAR(1000), @FindChar CHAR(1) = 'a'SET @Str = 'Hari,Jon,Ravi,Vijay,Peter,Max' --Input String
SELECT COUNT(1) AS CharCount
FROM (SELECT ID AS CharPosition
FROM dbo.Tally
WHERE ID <= LEN(@Str)
AND SUBSTRING(@Str, ID, 1) = @FindChar
) AS Temp
Here
is the output:
Split Comma Seperated values using Tally table
The
logic implemented in that function could be much simpler by using Tally table.
You can split the values without WHILE loop. It would be interesting to compare
the performance of these two mechanism.
--Split Comma
Seperated values
DECLARE @Str VARCHAR(1000), @Delimiter CHAR(1) = ','SET @Str = 'Hari,Jon,Ravi,Vijay,Peter,Max'
-- Append
delimiter at the beginning and end
SET @Str = @Delimiter + @Str + @Delimiter
SELECT SUBSTRING(@Str, ID+1, CHARINDEX(@Delimiter, @Str, ID+1) - ID-1) SplitedString
FROM dbo.Tally
WHERE ID < LEN(@Str)
AND SUBSTRING(@Str, ID, 1) = @Delimiter
Here
is the output:
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